How to pass arguments from a matrix to a function?

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Jacky Jo
Jacky Jo 2015-10-30
回答： Walter Roberson 2015-10-30
Hi,
I tried a lot to pass the elements of two matrixes (one by one) to a function which I created. I am not sure whether it is possible to call each element by element of a matrix to a function as a argument. Could you check and give an idea.?
I don't wanna use for loops anywhere in the code. I am trying to do by vectorized way.
Code is given below: Here Ylm(L_or_M,Lo,Co) is a function. instead of that you can use any random function which can give an output of 6x6 matrix.
L_or_M=5;
Co_latitude_grid=1:5;
Longitude_grid=5:8;
MaxLoop= length(Co_latitude_grid)*length(Longitude_grid);
Lo =repmat(Longitude_grid,length(Co_latitude_grid),1) % First matrx which has to be passed element by element
Co =repmat(Co_latitude_grid',1,length(Longitude_grid))% Second matrx which has to be passed element by element
Y_grid(6,6,MaxLoop)=zeros; % initilazation
Lo(Lo(1:1:end))
Y_grid(1:1:end) = Ylm( L_or_M,Lo(1:1:end),Co(1:1:end)); % Ylm() can be changed in to any arbitary function
% which can use Lo & Co matrix's elements one by one
% and produces a 6x6 matrix.

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采纳的回答

Walter Roberson
Walter Roberson 2015-10-30
result = arrayfun(@(L,C) Ylm(L_or_M, L, C), Lo, Co, 'Uniform, '0);
This is pretty much equivalent to
result = cell(size(L));
for K = 1 : numel(L)
result{K} = Ylm(L_or_M, Lo(K), Co(K));
end
Notice a cell array is being produced: this is necessary because you indicated that the function produces a 6 x 6 output. If the function produces a scalar output instead then
result = arrayfun(@(L,C) Ylm(L_or_M, L, C), Lo, Co);

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