Comparing vector elements by percentage

4 次查看（过去 30 天）
yousef Yousef
yousef Yousef 2015-11-1
回答： Image Analyst 2015-11-2
Angle=[5 10 20 60 180 190 195 300 310], these angles determine the possible directions of robots. If there are 2 robots starting with the same angle or plus minus 5%(5 degrees) they will make collision. I'd like to have the result in on vector such that:[2 2 1 1 1 2 2 1 1]. Any help?
  5 个评论
显示 3更早的评论
Stefan Raab
Stefan Raab 2015-11-2
编辑：Stefan Raab 2015-11-2
Hello,
the codeline
collision(i)= Angle(inToleranceIndexes)
won't work, if inToleranceIndexes has more than one value==1. Then Angle(inToleranceIndexes) i.e. is [300 310] and you can't assign a vector to a single element as you do with collision(i).
But a question in general: You say tolerance is 0.05*targetValue, that means your tolerance increases with increasing start-angle. Is this really how it is supposed to be?
Best regards, Stefan
yousef Yousef
yousef Yousef 2015-11-2
Hi,the tolerance is plus minus 5 degrees.The tolerance is fixed and can not be changed.I have another try,please check it.
  • Angle=[5 10 20 60 180 190 200 300 310];
  • collision=[];
  • for i=1:9
  • c=[];
  • targetValue = Angle(i);
  • tolerance = 0.5 * targetValue;
  • differences = abs(Angle-targetValue) ;
  • inToleranceIndexes = differences < tolerance;
  • withinTolerance = Angle(inToleranceIndexes);
  • c=[c;inToleranceIndexes];
  • end
  • collision=[collision;c];

请先登录，再进行评论。

请先登录，再回答此问题。

回答（1 个）

Image Analyst
Image Analyst 2015-11-2
As mentioned in your duplicate question there will be no collision unless you have different starting points. And all your code does is tell you that each angle interferes/collides with no other angle except itself, which is pretty useless.

类别

在 Help Center 和 File Exchange 中查找有关 Resizing and Reshaping Matrices 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by