Salam: I want to combine two or more row with same first column in the matrix .
from
A = [1 2 3 4;
1 5 6 1;
2 2 3 4;
2 5 6 1;
2 6 7 8;
3 1 2 3;
4 1 2 3
4 5 8 7];
to
A = [1 2 3 4 5 6 1 0 0 0;
2 2 3 4 5 6 1 6 7 8;
3 6 7 8 0 0 0 0 0 0;
4 1 2 3 5 8 7 0 0 0];

2 个评论

Why?
What kind of array do you want? A double with NaN in the "missing" columns on the right, or a cell array with nulls in the missing cells on the right?
Salam: I want to combine two or more row with same first column in the matrix .
from
A = [1 2 3 4;
1 5 6 1;
2 2 3 4;
2 5 6 1;
2 6 7 8;
3 1 2 3;
4 1 2 3
4 5 8 7];
to
A = [1 2 3 4 5 6 1 0 0 0;
2 2 3 4 5 6 1 6 7 8;
3 6 7 8 0 0 0 0 0 0;
4 1 2 3 5 8 7 0 0 0];

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 采纳的回答

Walter Roberson
Walter Roberson 2015-11-6

0 个投票

Numeric arrays cannot have different number of columns for each row.

2 个评论

Salam: I want to combine two or more row with same first column in the matrix .
from
A = [1 2 3 4;
1 5 6 1;
2 2 3 4;
2 5 6 1;
2 6 7 8;
3 1 2 3;
4 1 2 3
4 5 8 7];
to
A = [1 2 3 4 5 6 1 0 0 0;
2 2 3 4 5 6 1 6 7 8;
3 6 7 8 0 0 0 0 0 0;
4 1 2 3 5 8 7 0 0 0];
A1 = A(:,1);
[uA1, ~, idx] = unique(A1);
maxidx = max(idx);
maxmerge = max( histc(idx, 1:maxidx) );
Anew = zeros(maxidx, size(A,2)*(maxmerge - 1) + 1);
Anew(:,1) = uA1;
for K = 1 : length(idx)
targetrow = idx(K);
now put A(K,2:end) at the "end" of Anew(targetrow,:)
end
Now to put A(K,2:end) at the "end" of Anew(targetrow,:) is left as an exercise for you.
Note: you did not define the order of the row results when column 1 of A is not in sorted order. I picked an arbitrary order that aesthetically pleased me.
Note: you did not define the order of merging the rows that have the same column 1. I picked an arbitrary order that aesthetically pleased me.

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