removing elements of a cell array

2015 11 8
1 个回答
回答已采纳
更新时间：2015 11 8
1 次查看（30 天）

0 个投票

say we have a cell array
dictionary= 'abbreviately' 'abbreviation' 'abbreviator' 'abbreviatory' 'abbreviature' 'abby' 'abcoulomb' 'abdal'
I have written a code which returns x = 0 0 0 0 1 0 0
word='saddest'
newguess='e'
x=newguess==word
How do I delete the words from dictionary that are not equivalent for my x value and newguess letter 'e'. So x has a true value on the 5th position (after the 4 false values), which would mean I would like to delete all the words from dictionary if their 5th position letter does not equal 'e'. Thank you

请先登录，再回答此问题。

 采纳的回答

Walter Roberson
Walter Roberson 2015-11-8

0 个投票

newdictionary = C( cellfun(@(C) length(C) >= 5 & C(5)==newguess, dictionary, 'Uniform', 0) );

5 个评论
显示 3更早的评论 隐藏 3更早的评论

James Connor
James Connor 2015-11-8
Thanks a lot for that but also, is there a way to write it in a general sense for example if x= 0 0 1 0 1 or x= 0 1 1 0 0 0
Walter Roberson
Walter Roberson 2015-11-8
newdictionary = C( cellfun(@(C) length(C) == length(x) & all(C(x)==newguess), dictionary, 'Uniform', 0) );
James Connor
James Connor 2015-11-8
I'm so sorry I didn't define my dictionary correctly it should be
dictionary={'abbreviately';'abbreviation';'abbreviator';'abbreviatory';'abbreviature';'abby';'abcoulomb';'abdal'}
I apologise for the mistake.
Walter Roberson
Walter Roberson 2015-11-8
The code I gave assumed a cell array of strings, so it should be fine with that definition of your dictionary.
James Connor
James Connor 2015-11-8
Oh, I don't know if it's me doing something wrong but I keep getting this.
Index exceeds matrix dimensions.
Error in @(C)length(C)==length(x)&all(C(x)==newguess)

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Dictionaries 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by