calculate equality between adjacent elements in matrix
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Hello I have matrix A like that:
A=[7 7 3 5 6;1 1 7 5 6;6 6 5 5 5;1 1 3 3 3;1 1 7 7 7]
I want to move from this matrix 2 times. first from left to right and second from up to bottom. then on the baisis of these movements and equality between adjacent elements, matrix B1 and B2 are composed respectively. it means if from left to right movement adjacent elements are equal, the value of corresponding element in matrix B1 is 1. for example in this sample data B1 is like that:
B1=[1 0 0 0;1 0 0 0;1 0 1 1;1 0 1 1;1 0 1 1]
Also matrix B2 is composed on the basis of up to bottomn movement like that:
B2=[0 0 0 1 1;0 0 0 1 0;0 0 0 0 0;1 1 0 0 0]
I hope it is clear. Thank you
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Kirby Fears
2015-11-17
编辑：Kirby Fears
2015-11-17
You can create a logical matrix (1 for true, 0 for false) by simply checking equality:
B1 = ( A(:,2:end) == A(:,1:end-1) );
B2 = ( A(2:end,:) == A(1:end-1,:) );
The equality check with "==" operates element by element to return B1 and B2 as you requested.
If you want to check for approximate equality instead of precise equality, you can set a tolerance value and use subtraction in a similar manner.
tol = 1e-8; % Set tolerance
B1 = abs( A(:,2:end) - A(:,1:end-1) ) < tol;
B2 = abs( A(2:end,:) - A(1:end-1,:) ) < tol;
Hope this helps.
更多回答（1 个）
Andrei Bobrov
2015-11-17
B1 = diff(A,[],2)==0;
B2 = diff(A)==0;
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