Convert floating point to binary

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Hiii...
I want to ask how to convert floating point to binary in MATLAB
Thank you

采纳的回答

Andrei Bobrov
Andrei Bobrov 2012-1-7
e.g.:
a = 1234.57849; % your float point number
n = 16; % number bits for integer part of your number
m = 20; % number bits for fraction part of your number
% binary number
d2b = [ fix(rem(fix(a)*pow2(-(n-1):0),2)), fix(rem( rem(a,1)*pow2(1:m),2))]; %
% the inverse transformation
b2d = d2b*pow2([n-1:-1:0 -(1:m)].');
EDIT [16:32(UTC+4) 08.01.2012]
a = 1234.57849; % your float point number
n = 16; % number bits for integer part of your number
m = 25; % number bits for fraction part of your number
% binary number
d2b = fix(rem(a*pow2(-(n-1):m),2));
% the inverse transformation
b2d = d2b*pow2(n-1:-1:-m).';
  7 个评论
Walter Roberson
Walter Roberson 2020-12-3
As discussed below, for negative values, you need to be specific about which representation you want to use for the binary fraction.

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更多回答(5 个)

Oliver P
Oliver P 2016-8-10
Thank you for the cute and elegant solution! Unfortunately it's only working for positive floats. Negative floats will produce the same result as positive floats, but with negative bits. Which, of course, is not valid. And it's not the proper representation of negative values anyway.
  5 个评论
Oliver P
Oliver P 2016-8-12
Yes, I agree. As far as I'm aware Matlab uses IEEE-754 for all floating-point (single, double and custom) and for unsigned fixed-point calculations. Only for signed fixed-point it's using two's-complement representation.
Walter Roberson
Walter Roberson 2016-8-12
编辑:Walter Roberson 2017-2-10
The "Fixed Point Toolbox" can handle floating point numbers, but are only IEEE 754 if you request very specific formats.
I do not recall that the internal format for floating point number in the Symbolic Toolbox is documented.
The Fixed Point Toolbox offers Separated Sign. I would need to recheck to see if it offers One's Complement.

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Walter Roberson
Walter Roberson 2012-1-7
You need to define the fraction representation in binary.

Muammar
Muammar 2012-1-8
Thank you for all answers...

naghma tabassum
naghma tabassum 2016-10-12
编辑:Walter Roberson 2016-10-12

Aneesh paulsagin
Aneesh paulsagin 2018-3-16
编辑:Walter Roberson 2020-12-3
convert complex number to binary number
A = [-0.0040383664156692-0.00294191598222591i, ...
1.00279327279556+0.00768012699728154i, ...
-0.00226521017869135+0.00526418383309796i, ...
0.999498954084202-0.007158248828685i, ...
-0.00549315262581557+0.00808461388120792i, ...
0.998352426774419+0.00927983415466687i, ...
0.00736345881927219+0.00540426830690426i, ...
0.989408434745709-0.0144762821959683i, ...
0.00827899268722473+0.0122398877118786i, ...
0.999298739008971-0.0129949269950415i, ...
-5.47057549608037e-07-0.0130605748664198i, ...
1.01414402334238+0.0131228156923076i, ...
0.000678728159952879-0.00434397278237206i, ...
0.985341332736134+0.0239798712601118i, ...
0.0109818351271128-0.00658607972360998i, ...
1.01709879921672-0.00394256645505557i, ...
0.000335417716939878-0.00461609765687651i, ...
0.996785178287252-3.51718069407279e-05i, ...
-0.0137042758344959+0.00734580139566216i, ...
1.01389851161064+0.00526816880638668i, ...
-0.0143246406043654-0.0173541476823603i, ...
0.984838248467196-0.00274924075252472i, ...
-0.00383017735389232-0.00877400220581385i, ...
0.996013541706753+0.0113592028562242i, ...
-0.00607963966107746-0.00701052911751136i, ...
1.00401827238935-0.0163653626342944i]
  4 个评论
Walter Roberson
Walter Roberson 2021-10-18
format long g
A = [
1.01709879921672-0.00394256645505557i, ...
0.996013541706753+0.0113592028562242i, ...
-0.00607963966107746-0.00701052911751136i, ...
]
A =
1.01709879921672 - 0.00394256645505557i 0.996013541706753 + 0.0113592028562242i -0.00607963966107746 - 0.00701052911751136i
A_binary_out = reshape(dec2bin(typecast(reshape([real(A(:).'); imag(A(:).')], 1, []),'uint8'),8).',1, []);
tn = tempname(); %temporary file name
fid = fopen(tn, 'w');
fwrite(fid, A_binary_out, 'char');
fclose(fid);
fid = fopen(tn, 'r');
A_binary_in = char(fread(fid, [1 inf], 'uint8'));
fclose(fid);
pairs = typecast(uint8(bin2dec(reshape(A_binary_in, 8, []).')),'double');
A_reconstructed = pairs(1:2:end) + 1i .* pairs(2:2:end)
A_reconstructed =
1.01709879921672 - 0.00394256645505557i 0.996013541706753 + 0.0113592028562242i -0.00607963966107746 - 0.00701052911751136i
If your original A did not happen to be a column vector, then you will need a step to reshape it to the original size.

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