Replacing NaN with variable data

2015 11 20
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更新时间：2015 11 22
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hi, I have this matrices : u=[0;0;0;0;NaN;NaN;NaN;NaN;NaN;NaN;NaN;NaN] and up=[2;4;5;3;1;7;3;41] I wanna replace nan in "u" matrix with the variants of "up" matrix please answer to my question if you can , I really need the answer immediately, thanks

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Thorsten
Thorsten 2015-11-20

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This works is you have at least N values in up, where N is the number of NaNs in u.
u=[0;0;0;0;NaN;NaN;NaN;NaN;NaN;NaN;NaN;NaN];
up=[2;4;5;3;1;7;3;41]
ind = isnan(u)
u(ind) = up(1:nnz(ind))

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