replacing a number

I have a value D=[1 20]
another value F=[1 3 4 5 6 7 8 ]
no i want to compare two values D and F if value of F is not present in D in should be added to d1 ,i need a for loop.please help

 采纳的回答

setdiff(F,D)
ADD [13:44(UTC+4) 10.01.2012]
e.g. for every row of array F:
>> D = [1 20];
>> F =[1 3 4 5 6 7 8;
9 10 11 20 16 1 18];
>> out = arrayfun(@(i1)setdiff(F(i1,:),D),1:size(F,1),'un',0)
out =
[1x6 double] [1x5 double]
>> out{:}
ans =
3 4 5 6 7 8
ans =
9 10 11 16 18
>>

5 个评论

andrei can u tell how to process this please ,struck here for long
http://www.sendspace.com/file/scymbl
andrei ur equation returns error for value F having more than 1 column
??? Error using ==> setdiff at 51
A and B must be vectors or 'rows' must be specified.
Error in ==> new at 81
D1=setdiff(F,D)
setdiff(F(:),D)
thanks andrei can u answer to my other question which i posted
andrei i get answer for 1column but not for other columns

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