How to plot axis with origin (0,0,0) on 3D plot

16 次查看(过去 30 天)
I am using 3 matrices to form a 3D plot.
I am using the plot function >> line(S10,S20,S30, Axes=(0,0,0) 'linestyle', 'none', 'marker', '.', 'markeredgecolor', 'b', 'markersize', 0.1 ); view(3);
This is not the problem (I have tried using other plot functions and this is the only one that works).
However, on each of my axis I have positive and negative values but my axis are all positioned at the minimum value. How do i get the axis to be positioned at (0,0,0) with the above function?

回答(1 个)

Thorsten
Thorsten 2015-11-26
编辑:Thorsten 2015-11-26
Since R2015b, you can use
ax.XAxisLocation = 'origin';
ax.YAxisLocation = 'origin';
For older versions, have a look at this blog.
  2 个评论
Gregor Lees
Gregor Lees 2015-11-26
Sadly its version 2014b. Yeh I had seen that blog, unfortunately when I enter the following code,
>> line(S10,S20,S30, Axes = Origin, AxesOrigin = [0, 0, 0], 'linestyle', 'none', 'marker', '.', 'markeredgecolor', 'b', 'markersize', 0.1 ); view(3);
this error message appears,
line(S10,S20,S30, Axes = Origin, AxesOrigin = [0, 0, 0], 'linestyle', 'none', 'marker', '.', 'markeredgecolor', 'b', 'markersize', 0.1 );
Error: The expression to the left of the equals sign is not a valid target for an assignment.
(the highlighted part is the equals sign in "Axes = Origin")

请先登录,再进行评论。

类别

Help CenterFile Exchange 中查找有关 Axes Appearance 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by