How to store a vector under a for loop
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Hi, so I want to store theta as a vector under my for loop. But only the last number of theta saves, does anyone know how to get that as a vector?
clear all;
v = 5.8;
u = 1/v;
Psph = [509.35 507.06 504.77 398.20 394.19 389.61 268.71 266.99 265.85];
E = [];
r1= 6731;
r2= 6731;
pi = 3.1416;
theta=[];
for delta = [29 30 31 59 60 61 89 90 91]
theta = r1*sin(delta)*u;
end
E = Psph/((r1.^2)*(r2.^2)*4*pi*(u.^2)*sin(delta)*(cos(theta)).^2);
A = sqrt(E);
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采纳的回答
James Tursa
2015-11-26
编辑:James Tursa
2015-11-26
theta(delta) = r1*sin(delta)*u; % <-- Added the (delta) indexing
You will also need to change some of your matrix operators to element-wise operators. E.g.,
E = Psph./((r1.^2)*(r2.^2)*4*pi*(u.^2)*sin(delta).*(cos(theta)).^2);
But note that this entire loop:
for delta = [29 30 31 59 60 61 89 90 91]
theta(delta) = r1*sin(delta)*u;
end
can be replaced with these lines:
delta = [29 30 31 59 60 61 89 90 91]
theta = r1*sin(delta)*u;
更多回答(1 个)
Andrei Bobrov
2015-11-26
v = 5.8;
u = 1/v;
Psph = [509.35 507.06 504.77 398.20 394.19 389.61 268.71 266.99 265.85];
r1= 6731;
r2= 6731;
pi = 3.1416;
delta = [29 30 31 59 60 61 89 90 91];
theta = r1*sin(delta)*u;
E = Psph./((r1.^2)*(r2.^2)*4*pi*(u.^2)*sin(delta).*(cos(theta)).^2);
A = sqrt(E);
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