how to seek and replace characters on cell

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Now I have a mat A as below:
A=[1 1 1;1 2 2;2 1 2;2 2 1]
A =
1 1 1
1 2 2
2 1 2
2 2 1
Now want to replace '1' and '2' with 'a' and 'b' seperately; so I use function 'mat2cell()' to set mat A as cell B; but I don't know how shall I do the above replacement.

采纳的回答

Geoff Hayes
Geoff Hayes 2015-11-27
Rather than converting the matrix to a cell array using mat2cell, consider applying a function to each element of A using arrayfun. Define a mapping for 1 and 2 and apply that mapping to each element. For example,
map = {'a', 'b'};
We will treat the elements of A as indices into the map as
B = arrayfun(@(x)map(x),A);
where
B =
'a' 'a' 'a'
'a' 'b' 'b'
'b' 'a' 'b'
'b' 'b' 'a'
  6 个评论
vx2008
vx2008 2015-11-28
编辑:Geoff Hayes 2015-11-28
Thank you again. I have get it according to your guiding.
About the code data = mat2cell(data,ones(1,size(data,1)),ones(1,size(data,2))), it can be instead by data=num2cell(data).
Now I have get the data as below:
data
data =
'45 ℃' '2.2g' '5.0kg' [ 46]
'45 ℃' '3.0g' '7.0kg' [ 53]
'55 ℃' '2.2g' '7.0kg' [ 60]
'55 ℃' '3.0g' '5.0kg' [ 50]
[ 99] [ 106] [ 96] [ 0]
[ 110] [ 103] [ 113] [ 0]
[ 13.4444] [ 1] [ 32.1111] [ 0]
[161.4476] [4.0522e+03] [1.6211e+04] [2.2500]
then I run the code as below:
f=figure('Position',[0 60 120+C*80,30+R*20]);
t=uitable(f,'Data',data{:},'ColumnName',cname,'RowName',rname);
Then the Matlab complained that:
Error using cell/strmatch (line 19)
Requires character array or cell array of strings as inputs.
Error in uitable_parseold (line 41)
if (~isempty(strmatch(lower(args{index}),
oldpropnames, 'exact')))
Error in uitable (line 40)
if (nargout == 2) ||(uitable_parseold(varargin{:}))
so maybe I still should make some modification about it. I think I should convert all number's cells of data into character cells; and then convert data matrix into 1X1 matrix. but I don't know how?
Geoff Hayes
Geoff Hayes 2015-11-28
If you want to convert each element of the cell array to a string, then use cellfun to apply num2str to convert each number. For example, try
dataStr = cellfun(@(k)num2str(k),data,'UniformOutput',false);

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更多回答(1 个)

Stephen23
Stephen23 2015-11-27
There is no need to use complicated arrayfun, simply use A as an index:
>> A = [1 1 1;1 2 2;2 1 2;2 2 1];
>> map = {'a','b'};
>> B = map(A)

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