why is 1+ nan*1i = NaN + NaNi ?

I don't envision any workaround that would specifically make NaNs work. Speaking mathematically very loosely, the NaN in your original expression could be a "complex NaN", such that the NaN-ness leaks over to the real part.

I can imagine, without deep thinking, a couple workarounds, that are annoying in their own way, but might work in your particular situation.

Use another matrix dimension to keep real and imaginary parts separate
Define your own complex number object, that has the properties you outline above.

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Answer 2

Walter Roberson 2015-11-27

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/257852-why-is-1-nan-1i-nan-nani#answer_201397

在 MATLAB Online 中打开

A = complex(1,nan)
real(A), imag(A)
B = A

However if you were to do

2*A

then you would get complex(NaN, NaN). You can use complex() to force unusual structures such as complex(5,0) but any arithmetic on it is going to demote it to complex(NaN, NaN)

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Patrick Mboma 2015-11-28

Hi Walter,

Thanks for the reply. I did not know about the complex function. Thanks also for making me aware of it.

Your solution will surely work if I have a scalar. But if I start stacking items in a vector, I am not sure what the results will be. For now I think I will use the safe option of just creating another dimension to keep the numbers separate.

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