optimization function in matlab

2015 11 29
2 个回答
回答已采纳
更新时间：2015 11 30
3 次查看（30 天）

0 个投票

i would like to ask about the optimization in matlab function that works with multi variable input with each input has different boundaries the output is only one variables

请先登录，再回答此问题。

 采纳的回答

John D'Errico
John D'Errico 2015-11-29

1 个投票

help fmincon
Or, as found on the file exchange, fminsearchbnd.

5 个评论
显示 3更早的评论 隐藏 3更早的评论

mohammed hussein
mohammed hussein 2015-11-30
编辑：Walter Roberson 2015-11-30
thank you John D'Errico for answering me
i am trying these function a lot of time but it doesn't work
i have the equation
Function =(X-5)^2+(Y+6)^2+Z
when the boundary of
X from 0 to 1
Y from -1 to 2
Z from 2 to 3
i did that in matlab but i doesn't work
fun = inline('(x-5)^2+(y+6)^2+Z');
x0 = [1 1 1];
Lb=[0 -1 2];
Ub=[1 2 3];
[x,fval,exitflag,output] = fminsearch(fun,x0,Lb,Ub);
disp(fval)
it gives me error
Error in fminsearch (line 190)
fv(:,1) = funfcn(x,varargin{:});
Error in Untitled (line 5)
[x,fval,exitflag,output] = fminsearch(fun,x0,Lb,Ub);
can you help me with that problem
thank you
Walter Roberson
Walter Roberson 2015-11-30
fminsearch does not permit boundary conditions. As John indicated, you need to use fmincon() or you need to get the fminsearchbnd File Exchange contribution.
mohammed hussein
mohammed hussein 2015-11-30
thank you Walter Roberson i used the fmincon()
fun = inline('(x-5)^2+(y+6)^2+Z');
x0 = [1 1 1];
Lb=[0 -1 2];
Ub=[1 2 3];
[x,fval,exitflag,output] = fmincon(fun,x0,Lb,Ub);
disp(fval)
but also gives me the error
Error using fmincon (line 293) Row dimension of A is inconsistent with length of b.
Error in Untitled (line 5) [x,fval,exitflag,output] = fmincon(fun,x0,Lb,Ub);
John D'Errico
John D'Errico 2015-11-30
Read the help for fmincon.
You cannot simply pass in a list of variables in any order as arguments and expect fmincon to know that the 3rd and 4th arguments are to be interpreted as bounds.
READ THE HELP!!!!!
[x,fval,exitflag,output] = fmincon(fun,x0,[],[],[],[],Lb,Ub);
As you were passing in those arguments, fmincon thought they were to be treated as the equations for a set of linear INEQUALITY constraints. As such, what it thought were A and b were inconsistent in size.

请先登录，再进行评论。

更多回答（1 个）

Torsten
Torsten 2015-11-30

1 个投票

fun = @(x)(x(1)-5)^2+(x(2)+6)^2+x(3);
x0 = [1 1 1];
Lb=[0 -1 2];
Ub=[1 2 3];
[x,fval,exitflag,output] = fmincon(fun,x0,[],[],[],[],Lb,Ub);
disp(fval)
Best wishes
Torsten.

类别

在 帮助中心 和 File Exchange 中查找有关 Linear Least Squares 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by