How to transform a cell array of cells in a matrix

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ely may
ely may 2015-11-30
编辑： Image Analyst 2015-12-1
Problem: I have a cell array and every cell of this array has an other cell that contains a string: I want to trasform the cell array in a matrix of strings. How can i do? I have tried to use cell2mat but matlab gives an error:
'Cannot support cell arrays containing cell arrays or objects.'
I have A, in the attached .mat file, which is a vector of strings, and I want to divide prefix to postfix. To do it I use this code :
for k=1:25
[matches(:,k), postfix(:,k)] = regexp(A,sprintf('%d%d(.*)',digits{1}(k),digits{2}(k)),'match','once','tokens');
end
This code creates postfix (attached matlab.mat). I want that postfix is a matrix, and I don't know how transform it.
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Star Strider
Star Strider 2015-11-30
编辑：Star Strider 2015-11-30
The cell array in your ‘matlab.mat’ file seems to be 93% empty, and at least some of the non-empty cells contain only ''.

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回答（2 个）

Image Analyst
Image Analyst 2015-11-30
Extract it first, then use cell2mat:
for k = 1 : length(ca)
thisCellContents = ca{k}; % thisCellContents is another cell - the cell inside this cell.
matrix = cell2mat(thisCellContents);
end
Adapt as needed, for example if it's a 2D array of cells or whatever.
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Image Analyst
Image Analyst 2015-11-30
What did thisCellContents produce? Was there anything in it? Star Strider says your mat file is empty everywhere.
ely may
ely may 2015-12-1
编辑：ely may 2015-12-1
the matlab.mat file is not empty everywhere: if you control, it isn't while thisCellContents is empty.
Star Strider:
The cell array in your ‘matlab.mat’ file seems to be 93% empty, and at least some of the non-empty cells contain only ''.

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Stephen23
Stephen23 2015-11-30
编辑：Stephen23 2015-11-30
>> X = {{'A'},{'bb'};{'CCC'},{'d'}}
X =
{1x1 cell} {1x1 cell}
{1x1 cell} {1x1 cell}
>> Y = reshape([X{:}],size(X))
Y =
'A' 'bb'
'CCC' 'd'
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ely may
ely may 2015-12-1
编辑：ely may 2015-12-1
I have no secret! Now I post my code (I think it wasn't necessary). I add it in the question. Sorry but I think that the question was clear.
Image Analyst
Image Analyst 2015-12-1
Well it was necessary because we can now see that your code doesn't look like Stephen's code. Sorry, I have to leave for work now and I don't have time now to fix your code.

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