Can I use the matrix to the variable genetic algorithm?

2015 12 1
1 个回答
更新时间：2019 4 3
7 次查看（30 天）

0 个投票

I want use matrix to variable.
y=cost(gene)
gene = ones(1,10)
A = [0,find(gene(i,:))];
Pre_Num = numel(A);
S = 0;
up = 0.6;
Dec = 0;
for j = 1:Pre_Num-1
cost1 = exp(-(0.5*(A(j+1)-S)^2))
term = dec_rel_a + (( A(j+1) -A(j))*(1 -up));
Dec = A(j+1) - term;
predict = exp(-(0.5*(A(j+1)- Dec))^2));
if (((1 - RM_a)*0.1) > (predict_rel_a - RM_a))
dec_rel_a = 0;
gene(i,A(j+1)=2;
temp_fit_val(j) = temp_fit_val(j) + 10000
impro_rate = 1;
else
temp_fit_val(j) = temp_fit_val(j) + 10
impro_rate = up;
end
fit_val(i) = fit_val(i) + temp_fit_val(j);
Dec = Dec + (( A(j+1) - A(j))*(1 - impro_rate));
S = A(j+1) - Dec;
end
I would like to know the optimal arrangement of the matrix using a genetic algorithm.

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回答（1 个）

Alan Weiss
Alan Weiss 2015-12-1

0 个投票

Sorry, I do not understand your code or your question. If you are using Global Optimization toolbox, then your individuals must be row vectors for the ga function. If you are trying to optimize individuals that are matrices, then convert each individual to a row vector using the command
xnew = x(:)';
To convert a row vector back to a matrix, use reshape.
Alan Weiss
MATLAB mathematical toolbox documentation

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