Function to take grid reference

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keyboard_cuts
keyboard_cuts 2015-12-9
评论： Stephen23 2015-12-9
fairly new to this, would any body be able to tell me how i can create a function that can take a grid reference eg A10, C4, F6, etc and convert it into a row and column index? oh btw the grid has to be ten by ten!

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Stephen23
Stephen23 2015-12-9
编辑：Stephen23 2015-12-9
>> fun = @(s)[upper(s(1))-64,str2num(s(2:end))];
>> fun('A10')
ans =
1 10
>> fun('C4')
ans =
3 4
>> fun('F6')
ans =
6 6
  1 个评论
Stephen23
Stephen23 2015-12-9
Try this:
S = input('Enter the grid reference you wish to convert: ','s');
C = upper(S(1))-64
R = str2num(s(2:end))

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更多回答（1 个）

Walter Roberson
Walter Roberson 2015-12-9
Under the condition that it is 10 by 10 exactly,
r1 = GR(1) - 'A' + 1;
if length(GR) == 2
r2 = GR(2) - '0';
else
r2 = 10;
end
You do not specify whether the letters indicate rows or columns so make the appropriate choice [r1,r2] or [r2,r1]
If the grid can be larger than 10 x 10 then the "else" would have to be adjusted. If the grid can be larger than 26 then the r1 logic would need to be adjusted.
  2 个评论
Walter Roberson
Walter Roberson 2015-12-9
Note: Stephen's code is more compact; my code is more efficient for the particular requirements that were given.
keyboard_cuts
keyboard_cuts 2015-12-9
Thanks for your response, its much appreciated however like i said im new to this so im still a little unsure. My code now looks like
my_grid= zeros(10,10); %creates the matrix
GR=input('Enter the grid reference you wish to convert')%takes in input
r1 = GR(1) - 'A' + 1 if length(GR) == 2 r2 = GR(2) - '0' else r2 = 10 end however it still does not give me an output answer ie A1 =1,1 or C8= 3,8 or what have you

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