fopen works fine in *.m but fails in compiled Matlab

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Brian 2015-12-14

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评论： Brian 2015-12-15

I use something like:

            fpCSV = fopen(NameOfFile, 'rt');
            fgets(fpCSV);
            lineStr = fgets(fpCSV);
            fclose(fpCSV);

in my *.m file. It is actually buried in the method of a class that I wrote.

In interactive mode in Matlab, the script works great. I ran the Application Builder Tool and successfully compiled. However, when I run my application I get "Invalid file identifier" (see attached screenshot). How do I debug this?

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Brian 2015-12-14

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Compiler: Visual Studio 2012
Matlab Version: R2014a

File name acquired using:

NameOfFile = uigetfile('*.csv');

Brian 2015-12-15

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Solved...

Sorry for the waste of time... Need to include the complete path with

[NameOfFile, NameOfPath] = enduigetfile('*.csv');

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Answer 1

Guillaume 2015-12-14

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One important rule when dealing with user input, filesystem or anything else that is external to your program is to always make sure that it conforms to your expectations. In your particular case, that means checking that the file is actually open, i.e. check the value of fpCSV after the fopen call.

Another good practice is to only deal with absolute paths instead of relying on the current folder. I strongly suspect that is your problem here. The current directory is probably not the same in your executable as it is in interactive mode, and the file simply isn't in that directory. So:

[NameOfFile, PathOfFile] = uigetfile('*.csv');
[fpCSV, errmsg] = fopen(fullfile(PathOfFile, NameOfFile), 'rt');
if fpCSV == -1
   error('failed to open file %s because %s', NameOfFile, errmsg);
end