Fill blank spaces from lagged data with NaN

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Robert
Robert 2015-12-15
编辑： dpb 2015-12-16
I have a code which lags one data set in relation to another. The lag is determined based on r^2 values previously figured out.
The problem I have is that when the data is lagged, some data is removed. For example where there is a lag of +1 a vector of 96 rows becomes a vector of 95 rows. I want to fill that missing row is NaN so that it remains at 96. See code below. Thank you in advance for any help.
clear all;
clc
lag = load ('lagtime.txt'); %File contains the time by which each column will be lagged
A1 = load ('data\Anomalies\TWSA1anomalies.mat');
Approx1x = A1.TWSA1anomalies;
Approx1y = reshape(Approx1x,[1505,96]);
Approx1z = Approx1y';
NDVIdata = load ('data\Anomalies\NDVIanomalies.mat');
NDVIx = NDVIdata.NDVIanomalies;
NDVIy = reshape(NDVIx,[1505,96]);
NDVIz = NDVIy';
for j = 1:1505
m = lag(1,j)
GRACEcrop = Approx1z(1:(96-m),j);
NDVIcrop = NDVIz((1+m):96,j);
dlmwrite ('GRACECROPVEC.txt',GRACEcrop,'-append');
dlmwrite ('NDVICROPVEC.txt',NDVIcrop,'-append');
end
GRACEVEC = load ('GRACECROPVEC.txt');
NDVIVEC = load ('NDVICROPVEC.txt');
NEWGRACELAG = reshape(GRACEVEC,[96,1505]);

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dpb
dpb 2015-12-15
编辑：dpb 2015-12-16
Instead of selecting the first N points,
GRACEcrop = Approx1z(1:(96-m),j);
just set the last m to NaN...
Approx1z(end-m+1:end,j)=nan;
and then write the modified array. No need for a new array at all (unless you have reason to also keep the unmodified in memory as well, of course).
  2 个评论
Robert
Robert 2015-12-15
Thanks for your answer, however, it didn't seem to work, it made all of the output NaN. I'm also not sure that I understand your reference to changing the last m to NaN, as m is only 1 number per loop (generally 0-6).
dpb
dpb 2015-12-16
Oops, missed fixing up the index...see correction above...

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