Looping “aluminum” in reverse order, one letter per line should give result similar to this:
m
u
n
i
m
u
l
a

 采纳的回答

for letter = fliplr('aluminium')
disp(letter)
end

更多回答(1 个)

If this homework? Just use a for loop with a negative step
for k = length(yourString) : -1 : 1
fprintf('%s', yourString(k));
end
Adapt as needed. There are other ways too, like yourString(end-k+1) or using fliplr(yourString).

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