how do you make the results of a loop into table?

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here is my code
%start
syms 'x';
%to be able to input x
fun= input ('Enter function in terms of "x":');
%user input
f=inline(fun);
z=diff(f(x));
%differentiate in terms of x
f1=inline(z);
xo=input('enter initial value "xo":');
%input user initial value
x=xo;
for i=0:1000
y=x;
x=y-(f(x)/f1(x)) ;
if x==y
break
end
end
%loop
disp(['Root: ',num2str(x), ] );
disp('In the beginning, God said that the four dimensional divergence of an antisymmetric second rank tensor equals zero and there was light.');
%output up to 7 decimal places
m=input('Do you want to continue, Y/N [Y]:','s');
if m=='Y'
clc
newtonrap
else
clc
end
%ask to exit or continue
so, I want to take the answers of 'x','y',f(x) and f1(x) within the loop an make a table out of it. is that possible?
  3 个评论
rick arellaga
rick arellaga 2015-12-19
sorry dude i am new to this
now here is my code
if true
%start
syms 'x';
%to be able to input x
fun= input ('Enter function in terms of "x":');
%user input
f=inline(fun);
z=diff(f(x));
%differentiate in terms of x
f1=inline(z);
xo=input('enter initial value "xo":');
%input user initial value
x=xo;
disp(' f(x) f!(x) f(x)/f!(x) x')
disp('======== ======== ========= =========')
for i=0:250
fprintf('%8f %8f %8f %8f\n',f(x),f1(x),b,x)
y=x;
b=(f(x)/f1(x));
x=y-b;
if x==y
break
end
end
%loop
disp(['Root: ',num2str(x,8), ] );
% code
but now im getting the error using fprintf after i restarted matlab
end
Image Analyst
Image Analyst 2015-12-19
I don't see any table - that is a very specific special kind of variable. Looks like you're just printing a table to the command line without using a "table" variable. You forgot to give us the inputs you entered into this program. I, for one, will wait until you give us that.

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回答(1 个)

Renato Agurto
Renato Agurto 2015-12-18
Like Jan wrote, you should format your code and explain "table" in order to geta better answer. I only can guess you want a 2D-array:
Before the for loop:
your_table = zeros(1001,4)
in the for loop:
your_table(i,:) = [x y f(x) f1(x)];

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