How to get my for loop working?

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Inti Vanmechelen 2015-12-22

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编辑： Walter Roberson 2015-12-22

Hi,

I want to fill an empty matrix with values that equal the size of other matrices, being muscles. I tried looping over the different muscles, but the loop gives me a matrix with 6 times the size of last muscle, instead of 6 different numbers.

Here's my code:

Names2 = {'soleus', 'tibant', 'gaslat', 'vaslat', 'rectfem', 'hamlat'};
Vars2 = {soleus, tibant, gaslat, vaslat, rectfem, hamlat};
nvars = length(Vars2);
Duration = zeros(6,3);
for s = 1 : nvars
      for d = 1:6
          Duration(d,1) = length(IndexMuscleActGait.(names2{s}));
      end
  end

This gives me a matrix with in the first colum 6 times the number 50, which equals length of IndexMuscleActGait of the last muscle. However, I want the length of the 6 different muscles, and I can't find the right command to get it working.

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Answer 1

Walter Roberson 2015-12-22

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for s = 1 : nvars
  Duration(s,1) = length(IndexMuscleActGait.(names2{s}));
end

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Inti Vanmechelen 2015-12-22

编辑：Walter Roberson 2015-12-22

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That was really stupid of me not to think of that.. Thank you!

So no have 3 for loops:

for s = 1 : nvars
        Duration2(s,1) = length(IndexMuscleActGait.(names2{s}));
end
for s = 1 : nvars
        Duration2(s,2) = length(IndexMuscleActStairUp.(names2{s}));
end
for s = 1 : nvars
        Duration2(s,3) = length(IndexMuscleActStairDown.(names2{s}));
end

Would it be possible to get those 3 in one loop by looping over the matrix columns as well? I don't know how to do that, since I'm pulling data from 3 different matrices

Renato Agurto 2015-12-22

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 for s = 1 : nvars
        Duration2(s,1) = length(IndexMuscleActGait.(names2{s}));
        Duration2(s,2) = length(IndexMuscleActStairUp.(names2{s}));
        Duration2(s,3) = length(IndexMuscleActStairDown.(names2{s}));
 end

or

for s = 1 : nvars
      Duration2(s,1:3) = [length(IndexMuscleActGait.(names2{s})),...
                        length(IndexMuscleActStairUp.(names2{s})),...
                        length(IndexMuscleActStairDown.(names2{s}))];
end

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Answer 2

Renato Agurto 2015-12-22

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编辑：Renato Agurto 2015-12-22

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I think you should use

Duration(d,s) = ... %not Duration(d,1)

or maybe what you want is

Duration(d,1) = length(IndexMuscleActGait.(names2{d}));

if this last is correct, why do you have 2 for loops?

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Inti Vanmechelen 2015-12-22

That would mean I get 6 columns as well, and I only want 3.

Sorry, I didn't copy enough code for you to understand my full intention. The part I copied above has to give me 6 different numbers in the first column of the matrix.

Then I would repeat the same loop for IndexMuscleActStairUp (instead of Gait) and these 6 six numbers would fill the second column. Then i'd have a third column containing the lengths of IndexMuscleActStairDown.

So the 3 columns of 'Duration' cover the motion, the rows cover the lengths of the IndexMuscleActGait.(names2{s}) matrices.

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