How to concatenate array with delimeter?

Question

Laurensius Christian Danuwinata 2015-12-22

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评论： Laurensius Christian Danuwinata 2015-12-23

a1 = [0 32]; 
c1 = ([31 63]);
d1 = unique([a1 c1]);
first = ['[' num2str(d1(1)) ':' num2str(d1(2)) ']'];
second =['[' num2str(d1(3)) ':' num2str(d1(4)) ']'];
preresult= [ first second];
result = ['{' preresult '}'];
%result = {[0:31][32:63]}

How can I make this code worked more generally, for any values of a1 and c1? I've tried with this :

    newArray =[];
  for i=1:length(a1)
  newArray(length(newArray)+1)= [ '[' num2str(a1(i)) ':' num2str(c1(i)) ']' ]
  end
 But it said Subscripted assignment dimension mismatch. Can someone help me maybe? :(

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jgg 2015-12-22

Are you sure this is doing what you want it to? The matrix [0 32] is not the same as the matrix [0:32]?

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Answer 1

Guillaume 2015-12-22

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在 MATLAB Online 中打开

This looks to be related to your other question, so I'll reiterate here what I said there:

The bit pattern is not made up of strings, you're barking up the wrong tree. It is a cell array of double vectors and it's simply:

result = arrayfun(@(s, e) s:e, a1, c1, 'UniformOutput', false);

Or if arrayfun is too dauting for you, with a loop:

result = cell(size(a1));
for iter = 1:numel(a1);
   result{iter} = a1(iter) : c1(iter);
end

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Laurensius Christian Danuwinata 2015-12-23

在 MATLAB Online 中打开

Thanks Guillaume, I did this in the end : for iter = 1:numel(a);

result{iter} = ['[' num2str(a(iter)) ':' num2str(c(iter)) ']'];

end

HORE = char(['{' result '}']);

set_param('can_examples/Subsystem/CAN bit-packing 1','bitpatterns', HORE);

   and it worked, but just for the first iteration, afterwards it said, 
Error evaluating 'MassCallback' ...; Field assignment to a non-structure array object. 
If you don't mind, I can also send the files to you, regardless,
 it was the very big help from you, thanks once again :D