Help with improfile, profile between two selected points.

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Hi all,
Mine could be a really dumb question, but I'm having trouble in getting the image profile between two points. The two points should be provided by pairs of x and y coordinates, and, by using improfile or whatever function I'd like to have a 1d array of intensity points.
I've read the documentation, but this sentence is most obscure to me:
improfile(I,xi,yi) retrieves pixel intensity values, where I specifies an image, and xi and yi are equal-length vectors specifying the spatial coordinates of the endpoints of the line segments.
I really don't get what the function wants... I've tried something like:
profile = improfile(image,[1,1],[50,50])
But it returns me a number, insted of the intensity array between the two points 1,1 and 50,50....
Thanks in advance for your help.
Andrea

采纳的回答

Walter Roberson
Walter Roberson 2015-12-30
编辑:Image Analyst 2015-12-30
"image" is the primitive graphics function to create and display image objects. It would return the handle of the object. You should never use "image" as a variable name because of the risk that the MATLAB function might be referred to instead.
  3 个评论
Image Analyst
Image Analyst 2015-12-30
Andrea, you can "Accept this answer" (and your prior ones) to let people know it's been solved and to give the person who helped you credit (reputation points).

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更多回答(1 个)

Anuj Prajapati
Anuj Prajapati 2017-8-5
编辑:Anuj Prajapati 2017-8-5
If you're improfiling a matlab .fig file, auto improfiling like improfile(I,xi,yi) will return a null graph, while freehand manual improfiling will give you results. If you save the .fig file as an image like .tiff, it will generate an RGB separated graph.

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