Why does my anonymous function have an error?

2 次查看(过去 30 天)
I can calculate the integral for I1 but not for I2,I3 and I4. I'm new to matlab. I get the error as shown below. But when I plot the graph it's fine. Thanks
Index exceeds matrix dimensions.
Error in Q1d>@(x)(p2(1)*x((6:22)+1).^4)+(p2(2)*x((6:22)+1).^3)+p2(3)*x((6:22)+1).^2+p2(4)*x((6:22)+1)+p2(5)
Error in CompSimp (line 26)
fx = func(x);
Error in Q1d (line 61)
I2 = CompSimp(k,a,b,17)

采纳的回答

Guillaume
Guillaume 2016-1-2
It's difficult to answer in great details with so little information, but either x has less than 23 elements when your program reaches line 26 of CompSlim, or p2 has less than 5 elements when the anonymous function is declared.

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Loops and Conditional Statements 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by