how to split a forloop into columns
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I have written a code which contains a for loop but I need it to be seperated into columns. This is the code, however I would like each value of N to be a new column. Is there a way of doing that?
for N=1:12;
for m=1:12;
if mod(N, m)==0
disp '1'
else disp '0'
end
end
end
采纳的回答
Star Strider
2016-1-6
I am not certain what you want to do. See if this produces what you want:
N = 1:12;
m = 1:12;
[Nmat,mmat] = meshgrid(N,m);
modmat = mod(Nmat,mmat)==0;
Result = [Nmat(:) mmat(:) modmat(:)];
8 个评论
A123456
2016-1-6
Star Strider
2016-1-6
I’m not certain what you want. My ‘Result’ matrix has the values of ‘N’ in the first column, values of ‘m’ in the second, and the result of the corresponding mod operations on them in the third. That’s what I thought you meant by ‘separated into columns’.
Does reshaping it this way get closer to what you want:
Result3 = reshape(Result, size(N,2), size(m,2), []);
Here, ‘N’ is on the first ‘page’, ‘m’ the second, and the mod result the third. You can address it as you wish. For example to get the result for N=1:
N_1 = reshape(Result3(:,1,:), 12, 3)
N_1 =
1 1 1
1 2 0
1 3 0
1 4 0
1 5 0
1 6 0
1 7 0
1 8 0
1 9 0
1 10 0
1 11 0
1 12 0
For N=2, this becomes:
N_2 = reshape(Result3(:,2,:), 12, 3)
and so for the rest.
A123456
2016-1-6
Star Strider
2016-1-6
OK. If you only want a matrix of the mod operation, then that is just the ‘modmat’ matrix. You can omit the rest of the code.
A123456
2016-1-6
Star Strider
2016-1-6
I’ll be happy to!
If you only need the ‘modmat’ matrix, this is all you need of my code:
N = 1:12;
m = 1:12;
[Nmat,mmat] = meshgrid(N,m);
Result = mod(Nmat,mmat)==0;
I renamed it to be ‘Result’, since it seems to be what you want.
A123456
2016-1-6
Star Strider
2016-1-6
As always, my pleasure!
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