how to calculate number of zeroes in an image array?
1 次查看(过去 30 天)
显示 更早的评论
suppose i have an image array for example
1 2 3 1 2 1 1
0 1 2 5 8 7 9
4 7 8 9 2 3 0
0 0 0 1 2 0 0
the above array has 7 zeroes so how to calculate it using a matlab code
0 个评论
采纳的回答
Image Analyst
2016-1-10
Here are two ways:
m=[...
1 2 3 1 2 1 1
0 1 2 5 8 7 9
4 7 8 9 2 3 0
0 0 0 1 2 0 0]
numZeros = numel(m) - nnz(m)
numZeros = sum(sum(m==0))
5 个评论
Image Analyst
2016-1-10
I already showed you how to do that - find 0's. For example:
numZeros = sum(sum(m==0))
or in general, to find any integer:
countOfThisNumber = sum(sum(yourArray == yourInteger))
so, to count the 1's, you'd do this:
countOf1s = sum(sum(yourArray == 1))
Of course you can use whatever name for the variables you want. You don't have to use the names I used but I do encourage you to use descriptive names, rather than just single letters, so that your code is maintainable/understandable by others (and you) later, and not just an incomprehensible alphabet soup like we see far too often.
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Image Processing Toolbox 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!