impulse response from transfer function in matlab
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i have a transfer function given by
H(z)= 1-z^(-1)/1-z^(-1)+z^(-2)
how to find its impulse response h(n) in matlab what is the code for the same ?
采纳的回答
Star Strider
2016-1-12
This is how I would do it:
% H(z)= 1-z^(-1)/1-z^(-1)+z^(-2)
b = [1 -1];
a = [1 -1 1];
figure(1)
impz(b,a)
7 个评论
pavan sunder
2016-1-12
Star Strider
2016-1-12
Sure. Use the zplane function:
b = [1 -1];
a = [1 -1 1];
figure(2)
zplane(b,a)
pavan sunder
2016-1-12
pavan sunder
2016-1-12
Star Strider
2016-1-12
My pleasure.
MATLAB will plot in the available figure window, so to get two plots (the first using impz and the second using zplane), you have to specify two separate figures.
M.Moksha laxmi
2021-2-21
In the same problem what should I do if I want to plot the step response?
% H(z)= 1-z^(-1)/1-z^(-1)+z^(-2)
b = [1 -1];
a = [1 -1 1];
figure(1)
impz(b,a)
figure(2)
stepz(b,a)
.
更多回答（1 个）
Abdul Jabbar
2016-12-10
0 个投票
z^-1 -4z^-2 -2z^-4 can any one tell me that how i can find the impulse response of this function?
2 个评论
Petar Mostarac
2023-12-8
编辑：Petar Mostarac
2023-12-8
Is this a joke? :)
It is -1, -4 0 -2 and zeros to inf.
z^-1 is one sample delay, one step delay
Formarly, use basic knowladge to find H(z) in form H=b/a and then you can use:
h=impz(b,a, length_of_impulse_response)
In your question: b=[1 -4 0 -2] and a=[1 0 0 0]
If it is a joke, then is a good one :)
Paul
2023-12-8
Actually, the solution with impz should have: b = [0 1 -4 0 -2]
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