symbolic integral from parametric function?

2016 1 13
1 个回答
更新时间：2016 1 14
5 次查看（30 天）

0 个投票

I have a function which I want to get the integral from 0 to Inf but it is in parametric format and the only variable is w (inside the integral we will have dw) but there are lots of errors would you please help me:
clc
clear all
close all
syms k x y t
my_fun =@(w) (-2.*w+(2-(k+1)./w).*(1-(w.*y)-k)).*(exp(-w.*y)).*(exp(1j.*(w.*(x-t))));
q = int(my_fun,0,Inf)

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回答（1 个）

Star Strider
Star Strider 2016-1-14

0 个投票

This didn’t generate any errors, but it didn’t produce any useful output, either:
syms k x y t w
my_fun(w) = (-2.*w+(2-(k+1)./w).*(1-(w.*y)-k)).*(exp(-w.*y)).*(exp(1j.*(w.*(x-t))));
q = int(my_fun, w, 0, Inf)
q =
int(-exp(-w*y)*exp(-w*(t - x)*1i)*(2*w - ((k + 1)/w - 2)*(k + w*y - 1)), w, 0, Inf)
You will need to evaluate this numerically to get useful results.

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