Textscan error in code
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Hello
I try to run a matlab code for my data analysis and in the first step I get this error:
Error using textscan
Invalid file identifier. Use fopen to generate a valid file identifier.
Error in import_data (line 38)
dataArray = textscan(fileID, formatSpec, endRow(1)-startRow(1)+1, 'Delimiter', delimiter, 'EmptyValue' ,NaN,'HeaderLines', startRow(1)-1, 'ReturnOnError',
false);
Error in Ions_Pimms (line 58)
[x,y,tof,bid] = import_data(fname);
I do not understand how should I resolve this problem. Can some one help me? Thanks.
采纳的回答
Basically this means that fopen did not manage to open any file, and returned an error value instead of a valid file identifier. Usually this error occurs because no such file exists at the location with the name that the user passed to fopen. Alternatively that they have not passed any path information to fopen, which will then look only in the current directory.
The first step is to check the error code of fopen, and see what value it has. The fopen documentation explains that "If fopen cannot open the file, then fileID is -1.", so you should check this value. You might also like to check the second output, which is an error message:
[fileID,errmsg] = fopen(...);
And of course check the input to fopen, and confirm that it is the (path+)name of an existing file in that location.
2 个评论
Like many programming questions there is no "right" answer. Is the file in the current directory, or elsewhere? Are you using relative or absolute paths? How are you specifying the input to fopen? What is the input string to fopen when the error occurs?
You actually need to tell us some information about the situation, otherwise I have to rely on guessing or reading your mind.
Farzaneh ziaee
2016-1-14
更多回答（1 个）
Yuvasai Ayush
2023-5-31
0 个投票
The first step is to check the error code of fopen, and see what value it has. The fopen documentation explains that "If fopen cannot open the file, then fileID is -1.", so you should check this value. You might also like to check the second output, which is an error message:Basically this means that fopen did not manage to open any file, and returned an error value instead of a valid file identifier. Usually this error occurs because no such file exists at the location with the name that the user passed to fopen. Alternatively that they have not passed any path information to fopen, which will then look only in the current directory.
[fileID,errmsg] = fopen(...);
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