how to delete diagonal values in a matrix?

4 次查看(过去 30 天)
Hi everyone;
For example I got an matrix that all diagonal values are zero and I want to remove them.
A=[0 5 4 3
3 0 5 1
4 2 0 2
3 8 6 0]
I want to get a new matrix like that:
Anew=[ 5 4 3
3 5 1
4 2 2
3 8 6]
Is there any suggestion?
Regards...
  3 个评论
Guillaume
Guillaume 2016-1-18
Notwithstanding the fact that this will flatten A which is not what the OP is looking for, the find is completely unnecessary here.
A(A == 0) = [];
will produce the same result.
bilgesu ak
bilgesu ak 2016-1-18
I tried it but it gives a row vector that is:
[3 4 3 5 2 8 4 5 6 3 1 2]
I need a matrix that only diagonal values are gone but all rest is same...

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采纳的回答

Guillaume
Guillaume 2016-1-18
One possible way:
Anew = reshape(nonzeros(A'), size(A, 2)-1, [])'
  5 个评论
Stephen23
Stephen23 2016-1-18
+1 very nice solution (given zeros only on the diagonal...)
bilgesu ak
bilgesu ak 2016-1-21
thank you Guillaume, this solution only focuses on diagonals...

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更多回答(1 个)

shubhashree bal
shubhashree bal 2021-10-14
Try this:
A=[0 5 4 3
3 0 5 1
4 2 0 2
3 8 6 0];
u=1;
value =size(A,1)+1;
row_value_end=size(A,1)-1;
col_value_end=size(A,1);
for k=1:size(A,1)
u(k+1)=u(k)+value;
end
g= A.';
g(u(1:end-1))=[];
y= reshape(g,[row_value_end,col_value_end]);
b=y.';

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