linspace
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I want to create a vector which runs from 1 to 260 with increments of 360 between every whole number.
I can do this manually by: y=linspace(1,2,360); y1=linspace(2,3,360);... and so on.
By combining these I would have a vector which was 260*360=93600 long. However, there must be a easier way of doing this? preferably without a loop.
采纳的回答
the cyclist
2012-1-18
N = 260;
y = linspace(1,N,(N-1)*360+1);
6 个评论
Richard
2012-1-18
David Young
2012-1-18
So you don't want the increment to be 1/360?
the cyclist
2012-1-18
The change that you made will mean that the "fenceposts" will NOT exactly land on the integers. They will be off by increments of 1/(360*260). The +1 in my code was necessary to get the alignment correct. I suggest you get a feel for how this works by using smaller numbers than 260 and 360.
Richard
2012-1-18
David Young
2012-1-19
So maybe you need
linspace(1+1/360, n, (n-1)*360)
or
linspace(1, n-1/360, n, (n-1)*360)
Using linspace(1,n,(n-1)*360) is incorrect if the spacing between the points is meant to be 1/360. (See my answer below and the cyclist's comment above.)
Richard
2012-1-19
更多回答（1 个）
David Young
2012-1-18
If you concatenate the vectors y, y1 etc. the integer elements will be repeats. That is, it will go [1 1.0028 ... 1.9972 2 2 2.0028 ... ] and likewise at 3, 4 etc. Is that what you want, or do you really want it to go [1 1.0028 ... 1.9972 2 2.0028 ...]?
Assuming you actually want a linear sequence all the way through, you can just use
yall = linspace(1, 260, 259*360+1);
My choice of the final argument makes the difference between successive entries equal to 1/360, which I think is what you mean by increments of 360 between each whole number. If you use 260*360 for N, this will not be the case.
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