how to define a while statement that when the variable equals a numerical value, ends the code?

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Hi,
I want to write a while condition that when variable A gets a numerical value inside the loop, ends the code, otherwise continues to the code...
How can I write this while condition?
Thansks in advance,
Regards...

采纳的回答

Walter Roberson
Walter Roberson 2016-1-19
while ~exist('A', 'var') && ~isnumeric(A)
...
end
This will continue to loop until A is assigned a value and the value is numeric.
The common kinds of values that are not numeric include logical values, character strings, structures, cell arrays, function handles, graphics objects (R2014b or later), and various other kinds of objects.
  3 个评论
Walter Roberson
Walter Roberson 2016-1-19
while ~exist('A', 'var') || ~isnumeric(A) || isempty(A)
...
end
You would not need to initialize A at all
[] is type double and so is considered a numeric value. However I have added that as a condition.

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更多回答(1 个)

Titus Edelhofer
Titus Edelhofer 2016-1-19
Hi,
I understand the "get's value" is meant as "being not empty" ...?
A = [];
while isempty(A)
% do something, e.g.
A = 42;
end
Titus

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