Naming figures with existing filename

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10B
10B 2016-1-20
评论： 10B 2016-1-21
Hello Community,
I am having trouble getting the naming of my figures right. What I want to do is use part of a variable that contains an existing file name. For example: baseFileName = IMG_1234.jpg, and I want the title for the subsequent figure to read as, 'RGB 1234'. I have tried various iterations of code, an example of which is:
figure('name', 'RGB (regexpi(baseFileName, (?<=IMG_)\d+', 'match', 'once'))', 'numbertitle', 'off');
but obviously the section referring to 'regexpi(baseFileName,...etc.' would also appear in the title which is not what I want. The regexpi line of code has worked sucessfully elsewhere so I know this is correct, but I'm struggling to insert it in to the correct part of naming the figure.
This is for a script that will be run a few times using different images and I want to store the images after with their correct ID in the title for future reference.
So, can anyone offer some useful advice please?
Regards,
10B.

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Ilham Hardy
Ilham Hardy 2016-1-20
Perhaps this might works?
figT = ['RGB ' (regexpi(baseFileName, (?<=IMG_)\d+', 'match', 'once'))];
figure('name', figT, 'numbertitle', 'off');
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Ilham Hardy
Ilham Hardy 2016-1-21
Hello,
Apparently you've missed a colon in your example.
It should be:
figT = ['RGB ' (regexpi(baseFileName, '(?<=IMG_)\d+', 'match', 'once'))];
instead of
figT = ['RGB ' (regexpi(baseFileName, (?<=IMG_)\d+', 'match', 'once'))];
Hope this helps, IH
10B
10B 2016-1-21
Ah - the curse of the missing colon! (or single inverted comma). That's it, sorted perfectly. Thanks a lot for your help.

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Image Analyst
Image Analyst 2016-1-20
You're probably referring to the annoying feature of title where it treats the letter following an underline as a subscript. You can turn off that annoying default feature by using the 'Interpreter' option in title(), xlabel(), or ylabel():
baseFileName = 'IMG_1234.jpg';
[~, baseNameNoExtension, ~] = fileparts(baseFileName);
title(baseNameNoExtension, 'Interpreter', 'none'); % No subscript now - YAY!!!
Or if you just plain don't want the underline, replace it with a space:
baseFileName = 'IMG_1234.jpg';
[~, baseNameNoExtension, ~] = fileparts(baseFileName);
baseNameNoExtension(baseNameNoExtension == '_') = ' ';
title(baseNameNoExtension, 'Interpreter', 'none');
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10B
10B 2016-1-21
Do you know Image Analyst, your suggestion wasn't exactly what I was looking for, but, as it turns out is very good information in any case as I am now going to use this in the script to for generating the 'caption' title for the figure as well. Great stuff - thanks a lot for your input!

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