How to create a sequence of numbers on the GPU

Question

David Parks 2016-1-21

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https://ww2.mathworks.cn/matlabcentral/answers/264579-how-to-create-a-sequence-of-numbers-on-the-gpu

编辑： David Parks 2016-1-21

I want to do the follow in a new GPU Array, efficiently:

myarray = 1:100000

gpuArray(1:100000) works of course, but if I'm not wrong it's creating the large array in main memory then moving the whole thing to the GPU. I would expect that I can create the sequence of numbers on the GPU directly more efficiently, as I can do with many random numbers.

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Answer 1

Edric Ellis 2016-1-21

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https://ww2.mathworks.cn/matlabcentral/answers/264579-how-to-create-a-sequence-of-numbers-on-the-gpu#answer_206900

在 MATLAB Online 中打开

The direct equivalent is to use gpuArray.colon, like so:

myarray = gpuArray.colon(1,100000);

More here in the doc about building gpuArrays.

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David Parks 2016-1-21

编辑：David Parks 2016-1-21

在 MATLAB Online 中打开

Aha! Didn't see that one, thanks! Looks like it performs nearly the same as linspace, maybe 4ish percent faster.

>> tic; for i = 1:100000; gpuArray.linspace(1,100000,100000); end; toc;
Elapsed time is 9.975085 seconds.
>> tic; for i = 1:100000; gpuArray.colon(1,100000); end; toc;
Elapsed time is 9.486463 seconds.

Doesn't look like I can go back and edit the accepted answer after the fact, drat.

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Answer 2

David Parks 2016-1-21

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https://ww2.mathworks.cn/matlabcentral/answers/264579-how-to-create-a-sequence-of-numbers-on-the-gpu#answer_206870

在 MATLAB Online 中打开

Found it.

gpuArray.linspace(1,1000,1000);
>> tic; for i = 1:10000; gpuArray(1:100000); end; toc;
Elapsed time is 2.737965 seconds.
>> tic; for i = 1:10000; gpuArray.linspace(1,100000,100000); end; toc;
Elapsed time is 0.916697 seconds.