How to create a sequence of numbers on the GPU

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David Parks
David Parks 2016-1-21
编辑： David Parks 2016-1-21
I want to do the follow in a new GPU Array, efficiently:
myarray = 1:100000
gpuArray(1:100000) works of course, but if I'm not wrong it's creating the large array in main memory then moving the whole thing to the GPU. I would expect that I can create the sequence of numbers on the GPU directly more efficiently, as I can do with many random numbers.

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Edric Ellis
Edric Ellis 2016-1-21
The direct equivalent is to use gpuArray.colon, like so:
myarray = gpuArray.colon(1,100000);
More here in the doc about building gpuArrays.
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David Parks
David Parks 2016-1-21
编辑：David Parks 2016-1-21
Aha! Didn't see that one, thanks! Looks like it performs nearly the same as linspace, maybe 4ish percent faster.
>> tic; for i = 1:100000; gpuArray.linspace(1,100000,100000); end; toc;
Elapsed time is 9.975085 seconds.
>> tic; for i = 1:100000; gpuArray.colon(1,100000); end; toc;
Elapsed time is 9.486463 seconds.
Doesn't look like I can go back and edit the accepted answer after the fact, drat.

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更多回答（1 个）

David Parks
David Parks 2016-1-21
Found it.
gpuArray.linspace(1,1000,1000);
>> tic; for i = 1:10000; gpuArray(1:100000); end; toc;
Elapsed time is 2.737965 seconds.
>> tic; for i = 1:10000; gpuArray.linspace(1,100000,100000); end; toc;
Elapsed time is 0.916697 seconds.

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