How to find unique value in serial order??

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Triveni
Triveni 2016-1-26
评论： the cyclist 2016-1-26
I have a matrix
p = [90 90 -45 0 0 45 45 0 -45];
i want unique values in serial order from right side
q = [90 -45 0 45 0 -45];
Means from right side first value is -45, second is 0, third is 45...etc
I want repeated unique number according to serial from RHS.
Means sort repeated values.

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采纳的回答

the cyclist
the cyclist 2016-1-26
编辑：the cyclist 2016-1-26
Does this do what you want?
p = [90 90 -45 0 0 45 45 0 -45];
idx = [true diff(p)~=0];
q = p(idx);
If not, can you give another example or two that illustrates the rule?
  2 个评论
Triveni
Triveni 2016-1-26
The Cyclist Sir,
I have inserted an image. Here every p(9) values are interchange/swap by q(length(q-1)); and store & store temporary copy to c(:,:,1). then p(9) or c(1,9,1) interchange/swap by q(length(q-2)); and save temporary copy to c(:,:,2). then p(9) or c(1,9,2) interchange/swap by q(length(q-3)); and save temporary copy to c(:,:,3). and so on. can you make a program for me. I'll be very thankful to you.
the cyclist
the cyclist 2016-1-26
Is this a homework problem? If so, can you show some work that you tried yourself?
You can see my comment on Walter's solution, to see the way to get q.

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更多回答（1 个）

Walter Roberson
Walter Roberson 2016-1-26
q = p;
q(1+find(q(1:end-1)==q(2:end))) = [];
  2 个评论
Triveni
Triveni 2016-1-26
Thanks walter Sir, Actually i seen late...please solve my another query....can i find positions of matrix q according to p from RHS. means q= [90 -45 0 45 0 -45] & layer location according to p is [2 3 5 7 8 9]
the cyclist
the cyclist 2016-1-26
p = [90 90 -45 0 0 45 45 0 -45];
pLR = fliplr(p);
idxLR = [true diff(pLR)~=0];
locationsLR = find(fliplr(idxLR))

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