Function with double arguments

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Claudia Santos
Claudia Santos 2016-1-31
评论： Walter Roberson 2016-1-31
Can I make this?
function[g]= forward(f(x),x)
for j=5:5:40;
h=inv(j)
g=(f(x)+4*f(h)-f(h+h))/(h+h)
end
end

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the cyclist
the cyclist 2016-1-31
编辑：the cyclist 2016-1-31
You want to call a MATLAB function an argument that is itself a function, right? You can do that as follows. Define your function like this:
function [g] = forward(f,x)
for j=5:5:40;
h = inv(j);
g = (f(x)+4*f(h)-f(h+h))/(h+h);
end
end
and call it using a "function handle" like this:
forward(@sin,7) % Argument is the MATLAB built-in sine function
or like this
my_func = @(x) x^2; % Define your own function, and assign its handle
forward(my_func,7) % Argument is function defined by you
  2 个评论
Claudia Santos
Claudia Santos 2016-1-31
Oh thank you! Can you explain to me please this line of code?
my_func = @(x) x^2;
the cyclist
the cyclist 2016-1-31
It is an anonymous function.
So, if you now do
my_func(5)
you will get 25 as output.
The best form of thanks is to upvote and/or accept solutions that helped you. This rewards the contributor, and can point future users to helpful answers.

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