Converting hh:mm:ss into seconds

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tethys
tethys 2012-1-20
回答： Steven Lord 2021-9-1
Hi all,
I want to read the vectors which are hh:mm:ss (14:35:59.812) format and convert it to seconds. How can I do this in matlab?
Best

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采纳的回答

Andreas Goser
Andreas Goser 2012-1-20
Is this what you are looking for?
t='14:35:59.812';
[Y, M, D, H, MN, S] = datevec(t);
H*3600+MN*60+S
  4 个评论
显示 2更早的评论
per isakson
per isakson 2016-12-3
On R2016a I get the expected result
>> dt = datestr( now,'HH:MM:SS,FFF')
dt =
12:58:26,797
Arshey Dhangekar
Arshey Dhangekar 2021-9-1
I want to convert Time column ( HH:MM:SS) to min, there is a direct command time2num but it requires toolbox and it's paid.So without using time2num how can I convert into minutes. I tried with datetime also but I got error.
table=readtable('sample.csv'):
times = datetime(table.Time,'InputFormat','HH:mm:ss:SSS');
times = hour(times).*60 + minute(times) + second(times)./60;

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更多回答（3 个）

per isakson
per isakson 2012-1-20
The first and the last cell returns the result I think you are looking for. See help on DATENUM
datenum( '14:35:59.812', 'HH:MM:SS.FFF' ) .* (24*60*60) - ...
datenum( '00:00:00.000', 'HH:MM:SS.FFF' ) .* (24*60*60)
datestr( datenum( '00:00:00.000', 'HH:MM:SS.FFF' ), 'yyyy-mm-dd' )
datenum( '14:35:59.812', 'HH:MM:SS.FFF', 0 ) .* (24*60*60)
Peter Seibold
Peter Seibold 2021-4-18
About 100 times faster is:
t='14:35:59.812';
seconds=sum(sscanf(t,'%f:%f:%f').*[3600;60;1]);
Steven Lord
Steven Lord 2021-9-1
Ran in:
t='14:35:59.812';
F = 'hh:mm:ss.SSS';
du = duration(t, 'InputFormat', F, 'Format', F)
du = duration
14:35:59.812
format longg % To make s look nicer
s = seconds(du)
s =
52559.812

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