How to normalize a histogram?

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I am having an incredible amount of difficulty in finding a direct answer to this question. I have an array S that is 300x1. Using histogram(S) I obtain the following histogram:
This histogram is exactly what I need except for one problem. I want this to be a relative frequency histogram. As in, I want the y-axis values to be a percentage of the total number of data points (300). For example, the bin between 0.5 and 0.6 is approximately 73, so I would want it to read as (73/300) or 0.243.
I have seen many answers to this type of question telling users to use the hist function and then create a bar graph. I do not want a bar graph. I want the x-axis to remain unchanged as the actual data values, NOT as bin numbers. Can anyone help? Thanks!

采纳的回答

Sean de Wolski
Sean de Wolski 2016-2-2
  3 个评论
Sajid Afaque
Sajid Afaque 2020-6-12
@Sean de Wolski i am having the same issue but since i am using 2013b version the above syntax is not valid. do you have any idea of doing same using hist.
Owen Tolfrey
Owen Tolfrey 2020-12-18
[N,edges] = histcounts(y,'Normalization','probability');

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更多回答(2 个)

mayank awasthi
mayank awasthi 2018-8-7
if we want to find the area under this histogram then how can we do that?
  1 个评论
Moritz Flor
Moritz Flor 2018-9-21
Extract the bin values from the histogram, add them and multiply them by the bin width:
%%create histogram
x = randn(1000,1);
nbins = 25;
h = histogram(x,nbins)
%%extract parameters
counts = h.Values;
sum_counts = sum(counts);
width = h.BinWidth;
%%area of the histogram
area = sum_counts*width;

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george veropoulos
george veropoulos 2020-9-24
hi
i want to normalized the histogram
i use the hist
[f x]=hist(fn,nbins);
dx = diff(x(1:2));
bar(x,f./(sum(f.*dx)));
how i can use the histogram
thank you
  1 个评论
sadegh sehhat
sadegh sehhat 2022-1-4
编辑:sadegh sehhat 2022-1-4
insted of that you can use this code
if fn is your data set:
histogram(fn,nbins,'Normalization','pdf')

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