"solve" Function

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Patrick Star
Patrick Star 2011-3-7
编辑： Walter Roberson 2021-12-27
I'm trying to use the "solve" function to find a variable, but the other variables in the equation are input as opposed to defined. How do I fix this? Here's to illustrate what I'm trying to do using a simplified equation:
x=input('x = ')
y=input('y = ')
z=solve('x+y=z',z)
  2 个评论
Tebikew Alemu
Tebikew Alemu 2021-12-27
How i can write a matlab cod for a funtion
Walter Roberson
Walter Roberson 2021-12-27
编辑：Walter Roberson 2021-12-27
Ran in:
@Tebikew Alemu
Example:
syms x
y(x) = sin(x) - x^3/27 %this is the code for the function
y(x) = 
fplot(y, [-2*pi 2*pi])

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采纳的回答

Walter Roberson
Walter Roberson 2011-3-9
Did you solve the license problem? Until you have the software installed and licensed, solve() isn't going to work.
The answer you are looking for is along these lines:
syms x y z
xin = input('x =');
yin = input('y =');
zsol = solve('z-y=x', z);
disp(['z = ' char(zsol)]);
znum = double(subs(zsol, {x, y}, {xin, yin}));
disp(['z = ' num2str(znum)]);
  1 个评论
Patrick Star
Patrick Star 2011-3-9
I installed the software and this works. Thanks!

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更多回答（2 个）

Andrew Newell
Andrew Newell 2011-3-7
Here is one way:
x=sym(input('x = '))
y=sym(input('y = '))
syms z
z=solve(z-x-y,z)
  5 个评论
显示 3更早的评论
Andrew Newell
Andrew Newell 2011-3-8
Oh. I assumed that you were actually using the command "solve", which is in the Symbolic Toolbox.
Walter Roberson
Walter Roberson 2011-3-8
Please check to see whether you are licensed for the symbolic toolbox but perhaps have just not installed it. If you happen to be using the Student Edition than this could be the difficulty.
solve() is part of the symbolic toolbox and requires that toolbox be installed and licensed.

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Andrew Newell
Andrew Newell 2011-3-8
Is this what you're after?
x=input('x = ')
y=input('y = ')
z = x+y
  1 个评论
Patrick Star
Patrick Star 2011-3-8
In a way, yes. But the equations and variables are a lot more complicated than that and I don't have it already solved. I need to solve for z and find its value, but I can't figure out how to make the solve function give me both; in other words, I have an equation like z-y=x, and I want to input 1 and 2 for x and y and then have the output give me two things:
z = x+y
and
z = 3

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