I'm trying to use the "solve" function to find a variable, but the other variables in the equation are input as opposed to defined. How do I fix this? Here's to illustrate what I'm trying to do using a simplified equation:
x=input('x = ')
y=input('y = ')
z=solve('x+y=z',z)

2 个评论

How i can write a matlab cod for a funtion
Example:
syms x
y(x) = sin(x) - x^3/27 %this is the code for the function
y(x) = 
fplot(y, [-2*pi 2*pi])

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 采纳的回答

Did you solve the license problem? Until you have the software installed and licensed, solve() isn't going to work.
The answer you are looking for is along these lines:
syms x y z
xin = input('x =');
yin = input('y =');
zsol = solve('z-y=x', z);
disp(['z = ' char(zsol)]);
znum = double(subs(zsol, {x, y}, {xin, yin}));
disp(['z = ' num2str(znum)]);

1 个评论

I installed the software and this works. Thanks!

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更多回答(2 个)

Here is one way:
x=sym(input('x = '))
y=sym(input('y = '))
syms z
z=solve(z-x-y,z)

5 个评论

I tried that, but it returns this error:
??? Undefined function or method 'sym' for input arguments of type 'double'.
Error in ==> test at 1
x=sym(input('x = '))
Do you have the symbolic toolbox? What happens if you try
sym('x')
and
sym('1')
?
You do not really need the sym() calls for x and y:
x = input('x = ');
y = input('y = ');
syms z
z = solve(z-x-y,z);
I don't think I have the symbolic toolbox because this is what it returns when I try sim('x'):
??? Undefined function or method 'sym' for input arguments of type 'char'.
Error in ==> test at 1
sym('x')
Oh. I assumed that you were actually using the command "solve", which is in the Symbolic Toolbox.
Please check to see whether you are licensed for the symbolic toolbox but perhaps have just not installed it. If you happen to be using the Student Edition than this could be the difficulty.
solve() is part of the symbolic toolbox and requires that toolbox be installed and licensed.

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Is this what you're after?
x=input('x = ')
y=input('y = ')
z = x+y

1 个评论

In a way, yes. But the equations and variables are a lot more complicated than that and I don't have it already solved. I need to solve for z and find its value, but I can't figure out how to make the solve function give me both; in other words, I have an equation like z-y=x, and I want to input 1 and 2 for x and y and then have the output give me two things:
z = x+y
and
z = 3

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