Using unique command in a matrix
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Dear all, I would like to delete the columns of a matrix according to the unique values of its row. More specifically: Suppose to have this matrix: A =
1 2 3 3 3 5 6
11 14 16 16 16 14 16
I would like to select the unique values of the first row: [1 2 3 5 6] and create the matrix: A =
1 2 3 5 6
11 14 16 14 16
Anyone who can help me?
1 个评论
Matt J
2016-2-10
Your result is unambiguous only because in your example, the replicates of '3' in the first row coincide with replicates of '16' in the second row. What if the original matrix looks like this:
1 2 3 3 3 5 6
11 14 16 17 18 14 16
What goes under the '3' in the result? Will it be 16, 17, or 18?
回答（1 个）
Azzi Abdelmalek
2016-2-10
编辑：Azzi Abdelmalek
2016-2-10
A=[1 2 3 3 3 5 6
11 14 16 16 16 14 16]
B=unique(A','rows')'
Or maybe you want this
[ ~,jj]=unique(A(1,:))
B=A(:,jj)
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2016-2-10
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