What is the error here? Euler Method for 2nd order equations?

1 次查看(过去 30 天)
I have the following files and script file, but the graph is definitely wrong for the approximations. Any ideas?
Code:
clear all
% define the problem: function f and domain
f = @(t,y) (0*t+3*y);
a = 0; b = 1;
% exact solution, using a fine grid
t = a:.0001:b;
y = exp(3*t); % this is a vector of values, not a function
% coarse solution
h = .25;
ya = 1;
[T1,Y1]=euler(f,a,b,ya,h);
% fine solution
h = .05;
ya = 1;
[T2,Y2]=euler(f,a,b,ya,h);
% finer solution
h = .01;
ya = 1;
[T3,Y3]=euler(f,a,b,ya,h);
plot(t,y,'k',T1,Y1,'bo-',T2,Y2,'ro-',T3,Y3,'go-')
legend('Exact','h=0.25','h=0.05','h=0.01')
title('The Euler Method with 3 meshes')
Script File:
function[T,Y] = euler(f,a,b,ya,h)
a = 0; b = 1;
T = a:h:b;
Y = zeros(1,length(T));
Y(1) = a;
for k = 1 : length(T)-1
Y(k+1) = Y(k) + h*f(T(k),Y(k));
end

采纳的回答

Torsten
Torsten 2016-2-17
function[T,Y] = euler(f,a,b,ya,h)
a = 0; b = 1;
T = a:h:b;
Y = zeros(1,length(T));
*Y(1) = ya;*
for k = 1 : length(T)-1
Y(k+1) = Y(k) + h*f(T(k),Y(k));
end
Best wishes
Torsten.
  2 个评论
Kaylene Widdoes
Kaylene Widdoes 2016-2-17
So if I want to run the same code for (x^3)y' + 20(x^2)y = x, would I solve for dy/dx and then plug that equation in?

请先登录,再进行评论。

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 Least Squares 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by