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How to sort an array in descending order and you also have idea about the position to which it descend ?

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Arsal15
Arsal15 2016-2-20
评论： Roger Stafford 2016-2-21
I have an array of any length and I want to sort them in descending order. The position and value in that matrix refer to an ID of a node. So my question is that how I can sort this array in descending order and I should have idea of node position in array after sorting out.
Like I have a matrix A and the first value of the array is 5 but its ID is 1 and second value is 4 and its ID is 2 so after descending it goes to some new position 11 and 4 to 12 in the array. then whether i can get in a variable the position of variables after sorting out.
if true
A = [ 5 4 61 7 1 3 35 67 11 44 83 48 110 6]
B = sort (A, 'descend');
B = 110 83 67 61 48 44 35 11 7 6 5 4 3 1
ID_pos of 5 = 11 and ID_pos of 4 = 12 so how to get these index automatically.
end
Kindly guide me

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采纳的回答

Star Strider
Star Strider 2016-2-20
Use the ismember function:
A = [ 5 4 61 7 1 3 35 67 11 44 83 48 110 6];
B = sort (A, 'descend');
[~,Idx] = ismember([5 4], B)
Idx =
11 12

更多回答（1 个）

Roger Stafford
Roger Stafford 2016-2-21
You can use the second argument produced by 'sort':
[B,p] = sort(A,'descend');
q = 1:length(p);
q(p) = q;
The values in 'q' will give the indices with respect to 'B' of the corresponding positions in 'A'.

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