Function Sort to find smallest value in a Column?

I'm trying to find the five smallest value corresponding to their exact date from this weekly time series. What I wrote is the following:
tsStocks=fints(DATE, SP500)
Five_smallest_Value=sort(tsStocks,1,'ascend')
And i get this error:
Undefined function 'sort' for input arguments of type 'fints'.
Anyone able to tell me the right way to find them?
Thanks in advance.

回答(1 个)

Don't have Toolbox here so can't try it, but looks like you'll want the sortfts function to deal with a FTSOBJ

2 个评论

Now at least I don't get the error as before, but sortfts only help me to sort the date from the oldest to the most recent and not, as I would like, to sort the values from the bigger to the smaller or inverse. Thanks for the help.
From the above doc --
Arguments
tsobj
Financial time series object.
flag
(Optional) Sort order:
flag = 1; increasing order (default)
flag = -1; decreasing order
Of course, even if it didn't have the flag optional argument, simply reversing the increasing order after sorting will produce the decreasing order vector.

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提问:

2016-2-25

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dpb
2016-2-25

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