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Changing variable value after each loop interation and store them in array

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Karl Smith
Karl Smith 2016-2-26
回答： Roger Wohlwend 2016-2-26
I'm trying to store values in array xx and for each new loop iteration (i) i want the values divided by (j) to get stored in a new column (k).
My problem is that the (j) don't change for each new loop iteration and i get the same values for the entire array.
any one know how to solve this?
I want the variable 1/j in the first column to be j=0.01 and for the second column j=0.02 etc.
for i= 1:1:61
for k=1:1:8
for j=0.01:0.01:0.08
xx(i,k) = nthroot(Q(i)/((1/j)*B*(S0^(1/2))),5/3);
end
end
end
result
xx =
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841 0.7841
0.8302 0.8302 0.8302 0.8302 0.8302 0.8302 0.8302 0.8302
0.8747 0.8747 0.8747 0.8747 0.8747 0.8747 0.8747 0.8747
0.9177 0.9177 0.9177 0.9177 0.9177 0.9177 0.9177 0.9177
0.9594 0.9594 0.9594 0.9594 0.9594 0.9594 0.9594 0.9594
1.0000 1.0000 ...
Cheers!

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采纳的回答

Roger Wohlwend
Roger Wohlwend 2016-2-26
for i=1:61
for k=1:8
xx(i,k) = nthroot(Q(i)/((100/k)*B*(S0^(1/2))),5/3);
end
end

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