script wont run seems to be stuck in while loop
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I cant find out what is wrong with this script. Can anyone help out?
x=10^(-7);
count=0;
alp=1.24*10^(-10);
dx=10^(-9);
SIG0=0;
SIG1=0;
SIG2=0;
SIG3=0;
SIG4=0;
SIG5=0;
SIG6=0;
SIG7=0;
SIG8=0;
SIG9=0;
for i=1:9
n=i-1;
No=67465.6113/(2^(n/2)*(factorial(n))^(0.5));
while x>(-1.91*10^(-8)*(n+0.5)) && x<(1.91*10^(-8)*(n+0.5))
if n==0
SIG0=SIG0+(No^2)*(10^(-x^2/(2*alp^2)))^2*dx
elseif n==1
SIG1=SIG1+(No^2)*(2*x/alp)^2*(10^(-x^2/(2*alp^2)))^2*dx;
elseif n==2
SIG2=SIG2+(No^2)*(4*(x/alp)^2-2)^2*(10^(-x^2/(2*alp^2)))^2*dx;
count=count+1;
elseif n==3
SIG3=SIG3+(No^2)*(8*(x/alp)^3-12*(x/alp))^2*(10^(-x^2/(2*alp^2)))^2*dx;
elseif n==4
SIG4=SIG4+(No^2)*(16*(x/alp)^4-48*(x/alp)^2+12)^2*(10^(-x^2/(2*alp^2)))^2*dx;
elseif n==5
SIG5=SIG5+(No^2)*(32*(x/alp)^5-160*(x/alp)^3+120*(x/alp))^2*(10^(-x^2/(2*alp^2)))^2*dx;
elseif n==6
SIG6=SIG6+(No^2)*(64*(x/alp)^6-480*(x/alp)^4+720*(x/alp)^2-120)^2*(10^(-x^2/(2*alp^2)))^2*dx;
elseif n==7
SIG7=SIG7+(No^2)*(128*(x/alp)^7-1344*(x/alp)^5+3360*(x/alp)^3-1680*(x/alp))^2*(10^(-x^2/(2*alp^2)))^2*dx;
elseif n==8
SIG8=SIG8+(No^2)*(256*(x/alp)^8-3584*(x/alp)^6+13440*(x/alp)^4-13440*(x/alp)^2+1680)^2*(10^(-x^2/(2*alp^2)))^2*dx;
elseif n==9
SIG9=SIG9+(No^2)*(512*(x/alp)^9-9216*(x/alp)^7+48384*(x/alp)^5-80640*(x/alp)^3+30240*(x/alp))^2*(10^(-x^2/(2*alp^2)))^2*dx;
end
x=x+dx;
end
end
SIG0;
SIG1;
SIG2,
SIG3;
SIG4;
SIG5;
SIG6;
SIG7;
SIG8;
SIG9;
count
回答（1 个）
Adam
2016-2-26
Well, you know your own code domain and what it is supposed to do better than anyone. It is too detailed for me to just glance at and understand clearly what is intended, but if you say it remains in the loop infinitely then clearly:
x>(-1.91*10^(-8)*(n+0.5)) && x<(1.91*10^(-8)*(n+0.5))
is always evaluating to true.
Now that I look at the body of your while loop neither x nor n is changing in any of the branches of the loop so if the code ends up in the first place due to the above statement evaluating to true then the statement will always evaluate to true so far as I can see.
You are changing things within the while loop that have no impact on the condition against which the while loop is being tested.
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2016-2-26
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