error in using year()

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Binzi Shu
Binzi Shu 2016-2-29
编辑： Stephen23 2016-3-1
I typed exactly the same code as in the reference provided below:
Year = year('05-Aug-2003')
and I get
Year =
2002
2002
2002
2002
2002
2002
2002
2002
2002
2002
2002
Why is that? Thanks.
Reference:
http://www.mathworks.com/help/finance/year.html
  2 个评论
Fangjun Jiang
Fangjun Jiang 2016-2-29
what is the version of the Financial Toolbox?
ver('finance')
which -all year
Binzi Shu
Binzi Shu 2016-3-1
v5.6 for financial toolbox

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回答（1 个）

Fangjun Jiang
Fangjun Jiang 2016-3-1
编辑：Fangjun Jiang 2016-3-1
There must be a variable called "year" in the workspace. Try this:
year=2002*ones(120,1);
Year = year('05-Aug-2003')
It got your answer.
Try this
year=1:120;
Year=year('05-Aug-2003')
Year =
48 53 45 65 117 103 45 50 48 48 51
notice
>> double('05-Aug-2003')
ans =
48 53 45 65 117 103 45 50 48 48 51
It turned out it converted the string '05-Aug-2003' into double numbers and used the numbers to index the existing matrix "year". The size of "year" happens to be large enough so the "Index exceeds matrix dimensions" error didn't happen.
I don't like this behavior.
  2 个评论
Binzi Shu
Binzi Shu 2016-3-1
yes there is already a variable called year and it is a 1*n matrix. Does that mean that the year() function will not work properly if I ever created a variable called year? Thanks.
Stephen23
Stephen23 2016-3-1
编辑：Stephen23 2016-3-1
@Binzi Shu: that is correct. When you create a variable with the same name as an inbuilt function/variable, you cannot use the inbuilt one. For this reason avoid using length, size, cell, i, j, year, etc.
You can check if a name is already used with the which function.

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