Interpolating a velocity field between time steps
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Hi! I am a relatively new user of Matlab, working on a project of particle advection in a hydodynamic environment. In order to simulate the advection I have to interpolate current velocities between time steps. I have a field of mean current velocities for each day. I want to split the day into 4 hour intervals, hence I would need to interpolate the velocities at 5 extra time steps. My velocity matrix is named MER.u (92x100x15), where the third dimension represents each day (15 in total). When trying to interpolate I am returned with an error ("The grid vectors do not define a grid of points that match the given values.").
I am struggling to construct a sentence where I would tell Matlab to treat MER.u(:,:,it), to be the corresponding value of MER.mt(1). I am aware that a date giving a field of velocities is not exactly a function but I was assuming linear 1D interpolation is the correct method for this (of course I could and likely am wrong). Can you please help with this, it should be fairly easy.
The code I am using is given bellow.
%MER.mt is a vector of 15 dates in datenum format
%MER:u is a grid 92x100x15 of velocities for 15 days
tn= [MER.mt(1):1/6:MER.mt(end)] ;
interp1(MER.mt, MER.u, tn);
2 个评论
KSSV
2016-3-1
You have a grid of 92X100. There is spatial variation as well as temporal variation. How you can use interp1? Give more information about the problem and data you have.
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KSSV
2016-3-1
u = rand(92,100,15) ; % random xcomponent of veclocity
v = rand(92,100,15) ; % random ycomponent of velocity
t = linspace(1,150,15) ; % time steps
ti = [5,20,70] ; % time where velocities are to be interpolated
% Initialize interpolated components
ui = zeros(92,100,length(ti)) ;
vi = zeros(92,100,length(ti)) ;
for i = 1:92
for j = 1:100
% u comp interpolation
uij = squeeze(u(i,j,:)) ;
ui(i,j,:) = interp1(t,uij,ti) ;
% v comp interpolation
vij = squeeze(v(i,j,:)) ;
vi(i,j,:) = interp1(t,uij,ti) ;
end
end
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