I have an image (256 x 256) where its pixels ranging from 0 to 255. I need to built a look up table to map its values with image pixels.

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Neha W
Neha W 2016-3-1
评论： Neha W 2016-3-15
Since I am a beginner, I cant find a way as how to start with coding for lookuptable. It would really helpful if you would help.

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采纳的回答

Image Analyst
Image Analyst 2016-3-1
Use intlut(). Create your lookuptable, lut, then pass that plus your image into intlut() to get a new, transformed image.
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Image Analyst
Image Analyst 2016-3-1
编辑：Image Analyst 2016-3-1
Yes, you would have to have an image to apply the lut to. But you said you have a 256x256 image already. Just load up the lut and apply it and then show the image.
grayImage = imread('Cameraman.tif');
subplot(2,2,1);
imshow(grayImage);
title('Original Image');
grayLevels = 0:255;
fx = 2*grayLevels+3;
% Make lut
lut = uint8(mod(fx,5));
outputImage = intlut(grayImage, lut);
subplot(2,2,2);
imshow(outputImage);
title('Output Image in range 0-255');
subplot(2,2,3);
imshow(outputImage, []);
title('Output Image Scaled so you can see it');
Of course if you have a formula and operations, then you can just apply those directly like Florian showed, so you wouldn't need a lookup table. Originally you didn't show that formula and intlut() is good for cases where you have some totally general mapping of some gray levels into others.

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Florian Bendl
Florian Bendl 2016-3-1
Oh, if I see that correct, then you need no lookup tabel...just do:
im = imread('your file');
% Convert image to double in case it is in some other number format
im = double(im);
% Calculate f(x)
im = 2*im + 3;
% Apply modulo 5
Result = mod( im, 5 )
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Neha W
Neha W 2016-3-1
编辑：Neha W 2016-3-1
Oh. Thank you. It will surely help me a lot. One more thing, if I use different names to assign each step then, would that affect my result?

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