Solve Second Order Differential Equation with Initial Conditions
显示 更早的评论
I am trying to solve using the dsolve function:
D^2y/dt + p(dy/dt) + 2y = cos(w*t) with the conditions y(0) = 0 and y'(0) = 0
Assuming p = 0 and w cannot be 0.
Also how would I go about plotting the solutions of y(t) vs t for different values of w such as 0.5,0.6,0.7,0.8,0.9 and 0.95
How do I go about doing this?
采纳的回答
Star Strider
2016-3-3
Here you go:
syms y(t) p w t
p = 0;
Deq = diff(y,2) + p*diff(y) + 2*y == cos(w*t);
Y = dsolve(Deq, diff(y(0)) == 0, y(0) == 0);
Y = simplify(Y, 'steps', 20);
Yfcn = matlabFunction(Y)
As for the plot, you will find the meshgrid function significantly helpful here. Read about it and surface and mesh in the documentation.
3 个评论
Francisco Zapata
2016-3-3
Star Strider
2016-3-3
Use meshgrid to create your ‘t’ and ‘w’ matrices, then just give them to the ‘Yfcn’ anonymous function to create an output matrix, then plot the ‘t’ and ‘w’ matrices and the output matrix with surf or mesh.
Francisco Zapata
2016-3-3
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Calculus 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
